Note that the prime factorisation of 2501 is: 2501 = 41 ⋅ 61 With no square factors, the square root cannot be simplified. Note that 502 = 2500 so √2501 will be an irrational number a little more than 50. …

Explanation: #M_ (CO_2) = "220 mg"# #MW_ (CO_2) = "44.01 g/mol"# #"O"_2 " molecules = ?"#

So number of atoms in 0.5 mole of CH_4 is equal to number of molecules in 0.5 mol multiplied by 5. "number of atoms in 0.5 mole of CH_4"= "5⋅number of molecules in 0.5 mol" = …

(a+b)^2=24.01 >"note that " (a+b)^2=a^2+2ab+b^2 color (white) (xxxxx)=a^2+b^2+2ab color (white) (xxxxx)=12.85+ (2xx5.58) color (white) (xxxxx)=12.85+11.16=24.01

Oct 11, 2015 · 1545 subjects were given ginko & 1524 placebo. In ginko group, 246 developed dementian & in the placebo it was 277 with dementia. Significance level=0.01 to test claim (ginko is …

2.228 × 10^"23" molecules. 1 mole contains 6.022140857 × 10^"23" (Avogadro's number) The molecular weight of N_2O_3 is: 76.01 g/mol You have 28.3 g, so you have 28.3 / 76.01 = 0.37 mole Hence you …

The pendulum reaches a displacement of 10mm in 0.0314 s after crossing the equilibrium point. The frequency is 5 Hz and the amplitude is 0.012 m. One function that could result in the described …

The molality of the "CaCl"_2 is 1.14 mol/kg. > "Molar mass of CaCl"_2·"2H"_2"O" = "110.98 g + 36.03 g" = "147.01 g" "Mass of CaCl"_2 = 7.02 color (red) (cancel ...

Jan 16, 2017 · So #x=0.02mol# (Assuming the acid has been completely nutralized by 1g #CaCO_3#) Hence the strength of the #HCl# solution is #c= (0.02mol)/ (2L)=0.01M# So pH if the solution is #= …

The solutions are S= {160.6^@,305.7^@}. The max. and min. are =5 and -5 rcos (theta+alpha)=r (costhetacosalpha+sinthetasinalpha) =rcosthetacosalpha+rsinthetasinalpha) Comparing this to the …